2x^2-56x-1920=0

Solution for 2x^2-56x-1920=0 equation:

2x^2-56x-1920=0

a = 2; b = -56; c = -1920;
Δ = b2-4ac
Δ = -562-4·2·(-1920)
Δ = 18496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18496}=136$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-136}{2*2}=\frac{-80}{4}
=-20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+136}{2*2}=\frac{192}{4}
=48
$